Answer:
35.50
Explanation:
There are two stable isotopes, 35Cl (75.77%) and 37Cl (24.23%), giving chlorine a standard atomic weight of 35.45
HBr reacts with LiOH and forms LiBr and H₂O as the products. The balanced reaction is
LiOH(aq) + HBr(aq) → LiBr(aq) + H₂O(l)
Molarity (M) = moles of solute (mol) / volume of the solution (L)
Molarity of LiOH = 0.205 M
Volume of LiOH = 29.15 mL = 29.15 x 10⁻³ L
Hence,
moles of LiOH = molarity x volume of the solution
= 0.205 M x 29.15 x 10⁻³ L
= 5.97575 x 10⁻³ mol
The stoichiometric ratio between LiOH and HBr is 1 : 1.
Hence,
moles of HBr in 25.0 mL = moles of LiOH added
= 5.97575 x 10⁻³ mol
Hence, molarity of HBr = 5.97575 x 10⁻³ mol / 25.00 x 10⁻³ L
= 0.23903 M
≈ 0.239 M
Hence, the molarity of the HBr is 0.239 M.
The molecule with began to shake harder and become smaller so where they move together a lot faster
Answer:
0.00375 moles OF KHP
Explanation:
Equation of reaction of NaOH and KHP :
KHC₈H₄ O₄(aq) + NaOH(aq) → NaKC₈H₄O₄(aq) + H₂O(l)
the reaction required 25ml
Molarity = no of mole / volume in liters
no of moles = Molarity × volume in liters
no of moles of NaOH = 0.150 × (25/1000) = 0.00375 moles
using the balanced equation above
1 mole of NaOH requires 1 mole of KHP
therefore
0.00375 mole of NaOH will require 0.00375 mole KHP.