Answer:
4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)
This is an oxidation-reduction (redox) reaction:
4 N-III - 20 e- → 4 NII
(oxidation)
10 O0 + 20 e- → 10 O-II
(reduction)
NH3 is a reducing agent, O2 is an oxidizing agent.
Explanation:
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Alkanes are saturated hydrocarbon, that is they contain hydrogen and carbon without a double or triple bond between the carbon atoms, e.g. ethane, propane. Group 7a in the periodic table are called halogens e.g chlorine, bromine. Alkanes react with halogens in a reaction called substitution, where halogens replace hydrogen atoms in alkanes.
An atom of any element must contain "<span>(2) an equal number of protons and electrons" but it should be noted that atoms can borrow electrons from one another. </span>
Answer:
9.63 L.
Explanation:
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In this case, the undergoing chemical reaction is:

So the consumed amounts of hydrochloric acid and bromine are the same to the beginning based on:

In such a way, the yielded moles of hydrobromic acid and chlorine are:

Thus, the volume of the sample, after the reaction is the same as no change in the total moles is evidenced, that is 9.63L.
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150/30 = 5
HF1 20/2 = 10
HF2 10/2 = 5
HF3 5/2 = 2.5
HF4 2.5/2 = 1.25
HF5 1.25/2 = 0.625
Answer: 0.63g