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yulyashka [42]
2 years ago
5

2) What organization led the fight to stop this practice?

Chemistry
1 answer:
Lady bird [3.3K]2 years ago
5 0

Answer:

abolitionist movement

Explanation:

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The formula is CaCO3
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Using the equations
Anna [14]

Considering the Hess's Law, the enthalpy change for the reaction is 221.8 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: H₂ (g) + F₂ (g) → 2 HF (g)     ∆H° = -79.2 kJ/mol

Equation 2: C (s) + 2 F₂ (g) → CF₄ (g)     ∆H° = 141.3 kJ/mol

Equation 3: 2 C(s) + 2 H₂ (g) → C₂H₄ (g)     ∆H° = -97.6 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

<h3 /><h3>FIRST STEP</h3>

First, to obtain the enthalpy of the desired chemical reaction you need one mole of C₂H₄ (g) on reactant side and it is present in first equation. Since this equation has one mole of C₂H₄ (g) on the product side, it is necessary to locate it on the reactant side (invert it).

When an equation is inverted, the sign of ΔH° also changes.

<h3>SECOND STEP</h3>

Now, you need 2 moles of CF₄ (g) on the product side. The second equation has 1 mole of CF₄ (g) on the product side, so it is necessary to multiply it by 2 to obtain 2 moles of CF₄ (g).

Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

<h3>THIRD STEP</h3>

Finally, you need 4 moles of  HF (g) on the product side. The first equation has 2 moles of  HF (g) on the product side, so it is necessary to multiply it by 2 to obtain 4 moles of the compound.

Since the equation is multiply by 2, the variation of enthalpy also is multiplied by 2.

<h3>SUMMARY</h3>

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 H₂ (g) + 2 F₂ (g) → 4 HF (g)     ∆H° = -158.4 kJ/mol

Equation 2: 2 C (s) + 4 F₂ (g) → 2 CF₄ (g)     ∆H° = 282.6 kJ/mol

Equation 3: C₂H₄ (g) → 2 C(s) + 2 H₂ (g)     ∆H° = 97.6 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)     ΔH°= 221.8 kJ/mol

Finally, the enthalpy change for the reaction is 221.8 kJ/mol.

Learn more about molar enthalpy:

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Sharing of electrons always means its a covalent bond, and unequal means it is polar, so it is a polar covalent bond
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HBrO3 <br> A. All non metals “acid subcategory”
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Calculate the number of ATPs generated by the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol). Hydrolysis of
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Answer:

Explanation:

412 ATP's will be generated from the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol)

130 ATP from the oxidation of palmitate

22 ATP from the oxidation of glycerol

Altogether 130 + 22 = 412 ATP will be produced.

Here in case of tripalmitin (tripalmitoylglycerol), we have 51 carbons.

When 51 carbons can produce 412 ATPs

Then 1 carbon will produce how many ATPs = 412 ATPs/ 51 carbon= 8.1 ATPs.

This shows that ATP yield per carbon often oxidized will be 8.1 ATPs

Now we will see the ATP yield in the case of glucose.

Glucose is made up of 6 carbon and complete oxidation of glucose will produce 38 ATPs

When 6 carbons can yield 38 ATPs

Then 1 carbon can yield how many ATPs= 38 ATPs/ 6 carbons= 6.33 ATPs.

So, ATP yield per carbon in case of glucose will be 6.33 ATPs

8 0
3 years ago
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