Answer:
<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>
Step-by-step explanation:
The intercept form of a quadratic equation (parabola):
p, q - x-intercepts
Therefore
The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)
The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)
The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)
has two x-intercept at (-6, 0) and (6, 0)
The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))
has two x-intercepts at (-1, 0) and (-6, 0).
Answer:
y = 1/2x - 4
Step-by-step explanation:
If two lines are perpendicular to each other, they have opposite slopes.
The first line is y = -2x + 8. Its slope is -2. A line perpendicular to this one will have a slope of 1/2.
Plug this value (1/2) into your standard point-slope equation of y = mx + b.
y = 1/2x + b
To find b, we want to plug in a value that we know is on this line: in this case, it is (4, -2). Plug in the x and y values into the x and y of the standard equation.
-2 = 1/2(4) + b
To find b, multiply the slope and the input of x (4)
-2 = 2 + b
Now, subtract 2 from both sides to isolate b.
-4 = b
Plug this into your standard equation.
y = 1/2x - 4
This equation is perpendicular to your given equation (y = -2x + 8) and contains point (4, -2)
Hope this helps!
maybe xd ad something else please
Answer:
(P, Q) = (-75, 57)
Step-by-step explanation:
The equation will have infinitely many solutions when it is a tautology.
Subtract the right side from the equation:
Px +57 -(-75x +Q) = 0
x(P+75) +(57 -Q) = 0
This will be a tautology (0=0) when ...
P+75 = 0
P = -75
and
57-Q = 0
57 = Q
_____
These values in the original equation make it ...
-75x +57 = -75x +57 . . . . . a tautology, always true
The answer to this question is 360ft^2
