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3 years ago

Is 35 in , 45 in , 55 in, a right triangle or not

Mathematics

1 answer:

KonstantinChe [14]3 years ago

5 0

If its less than 90, its a right triangle. Hope this helps!

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Help Pls Asap!! Dont really understand the question

PolarNik [594]

Answer: B (the lower one)

Step-by-step explanation:

First let's solve for y.

x + 2y = 4

2y = -x + 4

y = -1/2x + 2

It is B since the y intercept for that graph is 2.

8 0

1 year ago

Read 2 more answers

PLEASSE HELLPPP 4

jeka94

the volume of a cone with a height of 27cm and a radius of 13cm is 4748.36242611007.Then you round it to the nearest tenth which would be 4,778.4 which would be the answer

you work out that by v=PI radius squared height divided by 3

6 0

2 years ago

DIscrete Math

Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

$f : X \rightarrow Y$ is surjective implies there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ .
If there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ , then $f : X \rightarrow Y$ is surjective

Let us start by the first implication.

Our hypothesis is that the function $f : X \rightarrow Y$ is surjective. From this we know that for every $y\in Y$ there exist, at least, one $x\in X$ such that $y=f(x)$ .

Now, define the sets $X_y = \{x\in X: y=f(x)\}$ . Notice that the set $X_y$ is the pre-image of the element $y$ . Also, from the fact that $f$ is a function we deduce that $X_{y_1}\cap X_{y_2}=\emptyset$ , and because $f$ the sets $X_y$ are no empty.

From each set $X_y$ choose only one element $x_y$ , and notice that $f(x_y)=y$ .

So, we can define the function $h:Y\rightarrow X$ as $h(y)=x_y$ . It is no difficult to conclude that $f\circ h(y) = f(x_y)=y$ . With this we have that $f\circ h=1_Y$ , and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function $h:Y\rightarrow X$ such that $f\circ h=1_Y$ .

Take an element $y\in Y$ , then $f\circ h(y)=y$ . Now, write $x=h(y)$ and notice that $x\in X$ . Also, with this we have that $f(x)=y$ .

So, for every element $y\in Y$ we have found that an element $x\in X$ (recall that $x=h(y)$ ) such that $y=f(x)$ , which is equivalent to the fact that $f$ is surjective. Therefore, the prove is complete.

3 0

2 years ago

Write a verbal expression for 3n-8

lisabon 2012 [21]

Answer: Pick anyone that suits you