The expression LaTeX: -5t^2+40t

Mathematics

1 answer:

dlinn [17]3 years ago

7 0

Answer:

8 seconds

Step-by-step explanation:

Given

h = - 5t² + 40t

When the object hits the ground then h = 0

Substitute h = 0 into the function and solve for t

- 5t² + 40t = 0 ← factor out - 5t from each term

- 5t(t - 8) = 0

Equate each factor to zero and solve for t

- 5t = 0 ⇒ t = 0

t - 8 = 0 ⇒ t = 8

t= 0 denotes the time of launch

t = 8 denotes the time it hits the ground

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