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guapka [62]
3 years ago
15

Help pleaseeeeeee!!!!!

Mathematics
2 answers:
raketka [301]3 years ago
7 0
Take a look at the tree diagram. The first branching shows the probabilities of there being oil, or not being oil.

Then, for each case we consider the probabilities of the kit being accurate or not.

we are interested in the branch Oil---Kit accurate---

Since P(Oil)=0.45, and P(Kit accurate)=0.8, the probability of there being oil and the Kit showing it correctly is:

0.45*0.8=0.36.

Answer: C) 0.36

fenix001 [56]3 years ago
5 0
The answer is C 0.36
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vova2212 [387]
X-3 is the expression that shows it
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Find the domain of the function.<br><br><br><br> f(x) = -5x + 3
Sedaia [141]

Enter a problem...

Calculus Examples

Popular Problems Calculus Find the Domain and Range f(x)=5x-3

f

(

x

)

=

5

x

−

3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

x

|

x

∈

R

}

The range is the set of all valid

y

values. Use the graph to find the range.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

y

|

y

∈

R

}

Determine the domain and range.

Domain:

(

−

∞

,

∞

)

,

{

x

|

x

∈

R

}

Range:

(

−

∞

,

∞

)

,

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3 0
2 years ago
(PLEASE HELP!!!)
Dennis_Churaev [7]
4.5% of 545 is 24.525, rounding to the nearest thousandth 24.53. (545 + 24.53 = $569.53
5 0
3 years ago
Simplify (2/9)^3<br><br> A. 8/729<br> B. 6/9<br> C. 2/729<br> D. 8/9<br><br> No guessing please
Lunna [17]
Eliminate the exponent
2^3=8
9^3=729

The simplified answer would be 8/729.

Hope this helps! 
7 0
3 years ago
Use the definition of a derivative to find f’(x).
tatyana61 [14]

Answer:

f'(x) = -\frac{9}{x^2}

Step-by-step explanation:

i) f(x) = 9 / x

ii) f'(x)  = $\lim_{h\to 0} \frac{f(x+h) - f(x)}{h} $  \hspace{0.2cm}

        = $\lim_{h\to 0} \frac{\frac{9}{x+h}  - \frac{9}{x} }{h}  =  \hspace{0.1cm} $\lim_{h\to 0} \frac{9x - 9(x+h)}{hx(x+h)} $ \hspace{0.1cm} =  \hspace{0.1cm}$\lim_{h\to 0} \frac{-9h}{hx(x+h)}  =  $\lim_{h\to 0} \frac{-h}{x(x+h)} = \frac{-9}{x^2}$

7 0
3 years ago
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