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Alika [10]
3 years ago
10

I need help with some maths homework what is the answer 3(x-3)=0

Mathematics
2 answers:
densk [106]3 years ago
8 0
If xy=0
assume that at least x or y=0

3(x-3)=0
therefor
3=0 or x-3=0
3=0 is false
therefor
x-3 mus equal zero
x-3=0
add 3 to both sides
x=3
tiny-mole [99]3 years ago
7 0
You would  have to use distributive property. it would come out to 3x-9=0 then you would add 9 to -9 and 0. It would then be 3x=9. You would then divide 9 and 3x by 3x. You will get x=3.
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Which statement best explains whether △JKL is congruent to △MNP?
Alchen [17]
Rotation of triangle JKL by 180 degrees will result in a triangle with corresponding vertices of (2, 4), (3, 2) and (-1, 2).

Then translating the resulting triangle 2 units up will result in a triangle with corresponding vertices (4, -2), (2, -3) and (2, 1) which is the same triangle as the given triangle MNP.

Therefore, the statement that best explains whether △JKL is congruent to △MNP is △JKL is congruent to △MNP because △JKL can be mapped to △MNP by a rotation of 180° about the origin followed by a translation 2 units up.
5 0
3 years ago
(100 points) Give a step by step explanation on how you solved this problem
Lina20 [59]
Use substitution
Given both y values, you know that they have to be equal

3x + 3 = x - 1
2x + 3 = -1
2x = -4, divide by 2
x = -2
Now plug x value into any of the equation to find y value
y = 3(-2) + 3
y = -6 + 3, y = -3

Solution: x = -2, y = -3
4 0
3 years ago
Read 2 more answers
Please help me the photo is my queston
Studentka2010 [4]

Answer:

i think it would be 30

Step-by-step explanation:

3 0
4 years ago
I'm inside the path I'm a difference of two numbers outside the paths what number am I
blsea [12.9K]
I think it is 0 because it is in the odd and even
7 0
4 years ago
For the right triangle shown, the lengths of two sides are given. Find the third side. Leave your answer in simplified, radical
mash [69]

Answer:

c=4√2

Step-by-step explanation:

Sine the triangle is a right triangle you can use the Pythagorean theorem. a^2+b^2=c^2

(4)^2+(4)^2=c^2

16+16=c^2

32=c^2

c=√32

c=4√2

6 0
3 years ago
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