Answer:
![n = 144m^2 - 1](https://tex.z-dn.net/?f=n%20%3D%20144m%5E2%20-%201)
Step-by-step explanation:
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<u>FACTS TO KNOW BEFORE SOLVING :-</u>
- Let x be a number. ⇒
can also be written as
.
- To make any variable the subject of any formula , we need to isolate it.
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According to the question ,
![3m = \frac{(n + 1)^{\frac{1}{2} }}{4}](https://tex.z-dn.net/?f=3m%20%3D%20%5Cfrac%7B%28n%20%2B%201%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%7B4%7D)
Lets multiply both the sides by 4.
![=> \frac{(n + 1)^{\frac{1}{2} }}{4} \times 4 = 3m \times 4](https://tex.z-dn.net/?f=%3D%3E%20%5Cfrac%7B%28n%20%2B%201%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%7B4%7D%20%5Ctimes%204%20%3D%203m%20%5Ctimes%204)
![=> (n + 1)^{\frac{1}{2} } = 12m](https://tex.z-dn.net/?f=%3D%3E%20%28n%20%2B%201%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%20%3D%2012m)
It can be also written as :-
![=> \sqrt{(n + 1)} = 12m](https://tex.z-dn.net/?f=%3D%3E%20%5Csqrt%7B%28n%20%2B%201%29%7D%20%3D%2012m)
Lets square both the sides.
![=> [\sqrt{(n + 1)} ]^{2} = (12m)^{2}](https://tex.z-dn.net/?f=%3D%3E%20%5B%5Csqrt%7B%28n%20%2B%201%29%7D%20%5D%5E%7B2%7D%20%3D%20%2812m%29%5E%7B2%7D)
![=> n + 1 =144m^2](https://tex.z-dn.net/?f=%3D%3E%20n%20%2B%201%20%3D144m%5E2)
![=> n = 144m^2 - 1](https://tex.z-dn.net/?f=%3D%3E%20n%20%3D%20144m%5E2%20-%201)
Answer:
This is a function y = mx + b:
- You start with $50, so the y-intercept(b) is 50.
- Adding $20 a week means that the slope(m) is 20.
So, the function would be y = 20x + 50, where y is the dollar amount after x weeks and x cannot be greater than 12.
I just finished the work and I came up with 7.52 sorry if it's wrong
It's a COMBINATION where 7 are chosen out of 11
₁₁C₇ = (11!)/(7! , 4!) = 330 combinations