Answer:
a = 
Step-by-step explanation:
To find the value of a, find the Slope of both the equations.
For lines to be perpendicular to each other 
For line 1:
2x + 3y − 6 = 0 represent the line in y=mx +c form
3y = -2x + 6
y = 
+ 
y = + 2
= 
For line 2:
ax - 3y = 5
ax = 5 + 3y
ax - 5 = 3y
y = 
= 
Apply the condition of perpendicularity:
* = - 1
a =
Answer:
C) (8,12)
Step-by-step explanation:
Answer: No
Step-by-step explanation: First, we need to understand that parallel lines are coplanar lines that do not intersect. On the other hand, perpendicular lines are lines that intersect at a right angle.
However, lines can't be both parallel and perpendicular because they either intersect each other at a right angle or never intersect.
So no, two lines can't be both parallel and perpendicular.
9514 1404 393
Answer:
y -2 = -2/3(x +4)
Step-by-step explanation:
There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.
That form is ...
y -k = m(x -h) . . . . . . . line with slope m through point (h, k)
__
The two marked points are (-4, 2) and (5, -4). All we need is the slope.
The slope is given by the formula ...
m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)
m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3
Using the first point, the equation for the line can now be written as ...
y -2 = -2/3(x -(-4))
y -2 = -2/3(x +4)
Answer:
2
Step-by-step explanation:
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