Hi
.... then it is located on the perpendicular bisector.
Answer:
Verified
Step-by-step explanation:
Let the diagonal matrix D with size 2x2 be in the form of
![\left[\begin{array}{cc}a&0\\0&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%260%5C%5C0%26d%5Cend%7Barray%7D%5Cright%5D)
Then the determinant of matrix D would be
det(D) = a*d - 0*0 = ad
This is the product of the matrix's diagonal numbers
So the theorem is true for 2x2 matrices
Answer:
x^3-10x^2+1/9
Step-by-step explanation:
For standard form you need to put the exponents in order. So x^3 is first, followed by -10x^2, and finally 1/9. Hope this helps!
Answer:
∠LOM is 48°
Step-by-step explanation:
∠MOL+∠MON=180°
6x°+12°+7x°-92°=180°
13x°-80°=180°
<em>Add 80° to both sides</em>
13x°=260°
<em>Divide both sides by 13</em>
x°=20°
Plugging x° into the equation for ∠LOM, we get:
7×20°-92°=
140°-92°=
48°
∠LOM is 48°
