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MrMuchimi
3 years ago
14

If the spinner shown is spun twice, what is the probability that it will land on 1 both times?

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Answer:

\frac{1}{4}

Step-by-step explanation:

When spinner is spun for the first time

Total events = {1,2,3,4,1,2,1,1} =8

Favorable events = {1,1,1,1} =4

So, probability = \frac{\text{Favorable outcomes }}{\text{Total outcomes}}

So, probability of getting 1 =  \frac{4}{8}

                                            =  \frac{1}{2}

When the spinner is spun for second time

Total events = {1,2,3,4,1,2,1,1} =8

Favorable events = {1,1,1,1} =4

So, probability = \frac{\text{Favorable outcomes }}{\text{Total outcomes}}

So, probability of getting 1 =  \frac{4}{8}

                                            =  \frac{1}{2}

So, probability that spinner will land on 1 both times : \frac{1}{2} \times\frac{1}{2}

                                                                                   =  \frac{1}{4}

Hence the probability of hat spinner will land on 1 both times is \frac{1}{4}

Brilliant_brown [7]3 years ago
3 0
I believe that it is one-half, it's B
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