Question

If the spinner shown is spun twice, what is the probability that it will land on 1 both times?

Answer 1

Answer:

$\frac{1}{4}$

Step-by-step explanation:

When spinner is spun for the first time

Total events = {1,2,3,4,1,2,1,1} =8

Favorable events = {1,1,1,1} =4

So, probability = $\frac{\text{Favorable outcomes }}{\text{Total outcomes}}$

So, probability of getting 1 =  $\frac{4}{8}$

                                            =  $\frac{1}{2}$

When the spinner is spun for second time

Total events = {1,2,3,4,1,2,1,1} =8

Favorable events = {1,1,1,1} =4

So, probability = $\frac{\text{Favorable outcomes }}{\text{Total outcomes}}$

So, probability of getting 1 =  $\frac{4}{8}$

                                            =  $\frac{1}{2}$

So, probability that spinner will land on 1 both times : $\frac{1}{2} \times\frac{1}{2}$

                                                                                   =  $\frac{1}{4}$

Hence the probability of hat spinner will land on 1 both times is $\frac{1}{4}$

Answer 2

I believe that it is one-half, it's B