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Mila [183]
4 years ago
12

Five percent of workers in a city use public transportation to get to work. A transit authority offers discount rates to compane

s that have at least 30 employees who use public transportation to get to work. You randomly select 3 companies and ask their employees if they use public transportation below. Complete parts (a) through (c).
(a) Company A has 291 employees. What is the probability that Company A will get the discount.

(b) Company B has 540 employees. What is the probability that Company B will get the discount.

(c) Company C HAS 1013 employees. What is the probability that Company C will get the discount.
Mathematics
1 answer:
Alex_Xolod [135]4 years ago
4 0

Answer:

a) the probability that Company A will get the discount is 0

b) the probability that Company B will get the discount is 0.2753

c) the probability that Company C will get the discount is 0.9986

Step-by-step explanation:

a) Let p(m) be the <em>minimum</em> proportion of workers needed at Company A who use public transportation to get to work in order the company can get discount offer by the transit authority.

Then p(m)=\frac{30}{291} ≈ 0.1031

The probability that Company A will get the discount can be stated as

P(z>z*) (p-value of z*) where z* is the z-score of 0.103 in the distribution of proportion of workers in the city who use public transportation to get to work.

z* can be calculated using the equation

\frac{p(m)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(m) is the minimum proportion needed for company A get discount (0.1031)
  • p is the proportion of workers in the city who use public transportation to get to work (0.05)
  • N is the number of employees of Company A (291)

Then z*=\frac{0.1031-0.05}{\sqrt{\frac{0.05*0.95}{291} } } ≈ 4.15

P(z>4.15)=1-P(z<4.15)=1-1=0

b) for Company B:

p(m)=\frac{30}{540} ≈ 0.0556

z*=\frac{0.0556-0.05}{\sqrt{\frac{0.05*0.95}{540} } } ≈ 0.597

P(z>0.597)=1-P(z<0.597)= 1-0.7247=0.2753

c) for Company C:

p(m)=\frac{30}{1013} ≈ 0.0296

z*=\frac{0.0296-0.05}{\sqrt{\frac{0.05*0.95}{1013} } } ≈ -2.979

P(z>-2.979)=1-P(z<-2.979)=1-0.0014=0.9986

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