Answer:
The 95% confidence interval for the percent of all black adults who would welcome a white person into their families is (0.8222, 0.8978).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
323 blacks, 86% of blacks said that they would welcome a white person into their families. This means that 
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the percent of all black adults who would welcome a white person into their families is (0.8222, 0.8978).
Answer:
a) 6 ways
b) 6 ways
Step-by-step explanation:
a) for all of the letters
for the first letter, we have 3 options
for the second, we have 2 options
for the third, we have 1 option
So the number of options will be;
3 * 2 * 1 = 6
b) for the first, we have 3 options, for the second, we have 2 options
so the number of options will be 3 * 2 = 6 options
$4680
Since 18% is 18/100 you just have to multiply the $842.4 by the reciprocal of that to find your answer
Reciprocal of 18/100 is 100/18
842.4* 100/18 equals 84240/18
84240/18 equals 4680
Answer:
87 / 100 I do believe will be your answer.
Step-by-step explanation:
1 is the greatest common divisor of 87 and 100, and therefore the result can't be further reduced. I hope this helps!