What is the perimeter of the trapezoid graphed below?

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

5 0

Each slanty side is sqrt(29).
So the perimeter is 8+2sqrt(29) .

Zanzabum3 years ago

3 0

To get the perimeter of the trapezoid, we will add the lengths of the 4 sides together.
So, first we will need to get the length of each side.

Base of trapezoid = 8 - 2 = 4 units
The upper edge of the trapezoid = 6 - 4 = 2 units

Now, for the two side edges, we can note that they are both equal. So, we need to get only one length (as the other would be the same). I will get the length of the left side.
Coordinates of the start point are (2,4) which represent (x1,y1)
Coordinates of the end point are (4,9) which represent (x2,y2)
To get the distance between the two points, we will use the rule attached in the image below as follows:
distance = sqrt ((4-2)^2+(9-4)^2)
distance = √29
Therefore, each of the side edges equal √29 units

From the above, we can now easily get the perimeter as follows:
perimeter = 6 + 2 + √29 + √29
perimeter = 8 + 2√29 units

Based on the above calculations, the best choice would be:
D. 8 + 2√29 units

You might be interested in

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$