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Natasha2012 [34]
3 years ago
10

Can someone help me Please

Mathematics
2 answers:
gulaghasi [49]3 years ago
7 0

Answer:

6x^3+6y^3+10

Step-by-step explanation:

marta [7]3 years ago
3 0

Answer:

I do not know llolshdhdhhshshdhhdhdhshxhzhhzhxhsfzhlzhhz

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Plz Hurry
salantis [7]
The answer would be c, a line is different from a line segment because a line continues on in both directions
3 0
3 years ago
Read 2 more answers
Help (20 points) Literal Equations
Vesna [10]

I'm not sure if you were supposed to add two numbers together to get five? If that's the case the answer would be 5/3. If it's not i'm sorry, I tried.

5 0
3 years ago
Read 2 more answers
In a study conducted in the United Kingdom about sleeping positions, 1000 adults in the UK were asked their starting position wh
Lady_Fox [76]

Answer: = ( 0.411, 0.409)

Therefore at 95% confidence interval (a,b) = (0.411, 0.409)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean gain x = 0.41

Standard deviation r = 0.016

Number of samples n = 1000

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

0.41+/-1.96(0.016/√1000)

0.41+/-1.96(0.000506)

0.41+/-0.00099

0.41+/-0.001

= ( 0.411, 0.409)

Therefore at 95% confidence interval (a,b) = (0.411, 0.409)

4 0
4 years ago
A Quadratic Equation factors to (x-4)(x+6) the solutions to this are
Karo-lina-s [1.5K]
I hope this helps you



x.x+x.6-4.x-4.6



x^2+6x-4x-24


x^2+2x-24
3 0
3 years ago
Can someone help me with these questions. Even if you can only help me with one, it would be appreciated.
prohojiy [21]

Try these solutions:

<u>Task 1.</u>

a) the required angle is arctan(CG/AC);

b) according to the condition CG=AE=11.4 (cm.);

c) BC=EH=9.6 (cm.), then

AC=\sqrt{AB^2+BC^2}=\sqrt{18.4^2+9.6^2}=\sqrt{430.72} (cm.);

d) the required angle is:

arctan\frac{CG}{AC}=arctan\frac{11.4}{\sqrt{430.72}}=arctan(0.549297)=28.5=29

Answer: 29°

<u>Task 2.</u>

a) the required angle is EFV (see the attached picture): arctan(EV/FE);

b) to calculate FE: FE=0.5AB=7.25 (cm.);

c) to calculate EV:

EV=\sqrt{DV^2-DE^2} =\sqrt{17.2^2-(14.5/\sqrt{2})^2}=13.80996 (cm.);

d) to calculate the required angle:

m(∠EFV)=arctan(13.80996/7.25)=arctan(1.9048)≈62.302°=62°.

Answer: 62°

8 0
3 years ago
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