I don’t understand the equation. What am I solving for?
The right answer is B.
The first step to answering this question is combining all like terms.
A. 2x + 2 + 2x + 3x - 8
The like terms in this expression are the x terms and the constants
So, what you would do is combine all of the x terms and combine all of the constants
(2x + 2x +3x) + (2 - 8)
7x - 6
B. 4 + 7x - 2
In this expression, you would combine all of the constants
7x + (4 - 2)
7x + 2
C. -2 + 5x + 2x - 4
For this expression, you would again, combine all of the x terms and all of the constants.
-2 + 5x + 2x - 4
(5x + 2x) + (-2 - 4)
7x - 6
D. 8x - x - 6
For this expression, you would combine all of the x terms
8x - x - 6
(8x - x) - 6
7x - 6
Now let's look at all of the new answer choices:
A. 7x - 6
B. 7x + 2
C. 7x - 6
D. 7x - 6
The question is asking you to find the one expression that's different. The only different one is B, so that's the answer.
5 girls to 2 boys, it’s not asking for boys and girls
Answer:
x = 1000
Step-by-step explanation:
5,350 ÷ x = 5.35
To find this you should divide 5,350 by 5.35.
5,350 ÷ 5.35 = 1000
x = 1000
Answer: 0.0548
Step-by-step explanation:
Given, A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.05.
Let 
represents the sample mean GPA for each student.
Then, the probability that the random sample of 100 male students has a mean GPA greater than 3.42:
![P(\overline{X}>3.42)=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{3.42-3.5}{\dfrac{0.5}{\sqrt{100}}})\\\\=P(Z>\dfrac{-0.08}{\dfrac{0.5}{10}})\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=P(Z>1.6)\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28%5Coverline%7BX%7D%3E3.42%29%3DP%28%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%3E%5Cdfrac%7B3.42-3.5%7D%7B%5Cdfrac%7B0.5%7D%7B%5Csqrt%7B100%7D%7D%7D%29%5C%5C%5C%5C%3DP%28Z%3E%5Cdfrac%7B-0.08%7D%7B%5Cdfrac%7B0.5%7D%7B10%7D%7D%29%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%5D%5C%5C%5C%5C%3DP%28Z%3E1.6%29%5C%5C%5C%5C%3D1-P%28Z%3C1.6%29%5C%5C%5C%5C%3D1-0.9452%3D0.0548)
hence, the required probability is 0.0548.
