Answer:
D: 14q + 21√qr
Step-by-step explanation:
We want to find the product of;
(2√q + 3√r) and 7√q.
Where p and q are integers.
Using distributive property, we have;
(2√q × 7√q) + (3√r × 7√q)
>> 14q + 21√qr
Correct option is D
3/5*10 is the same as 3/5*10/1 and it should be 30/5 which is the same as 6.
So, 3/5*10 is 6
Answer:
4x/x^-5x^3
Step-by-step explanation:
^ represents the exponent
<span>
Answer: PQ=5, QR=radical 61= 7.81, angle: 50degrees,</span>Why:PQ=|-3|+2=5PR=6<span>angle Alfa, so there is right angle triangle PQR so I can use following formula:</span>PQ^2 + RP^2=QR^2;25 + 36=QR^2;QR=radical 61<span>also I can use: sinus (angle)=PR/QR;</span><span>sin(angle)=6/radical61=0.76822 which gives angle to be little bit more than 50 degrees{sinus 50 degrees=<span>0,7660</span>}. </span>
