Answer:
0.8 ft³/min
Step-by-step explanation:
Assuming that the cross section formed by the water at a depth of x is b. Then, if we use the property of similar triangles we have...
See the attachment for the workings.
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Continuation of the workings
From the question, we're told that the water is 6 inches deep. Converting this inch to ft, we have
6 ft = 0.5 ft.
So we use 0.5 as our x, and then use 12 ft³/min as our dV/dt. Doing this, we have
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12 = 30 * 0.5 dx/dt
12 = 15 dx/dt
dx/dt = 12/15
dx/dt= 0.8 ft³/min
The equation for a ball thrown straight up is:
y = v₀t - 0.5gt²
We don't know the initial velocity of the ball. We use the given condition from the problem that the maximum height was achieve after t = 2
y = 2v₀ - 19.62
v₀ = 0.5y + 9.81
Substituting, factoring, and replacing t with x, the result is:
<span>y = –16(x – 2)^2 + 68</span>
C. Divide the previous value by 5
Answer:
The equation becomes
Therefore,
Hence, option (C) is true.
Step-by-step explanation:
Given the expression
Solving the L.H.S of the equation
Converting improper fraction to a fixed number:
Thus, the equation becomes
Therefore,
Hence, option (C) is true.