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Anna71 [15]
3 years ago
14

Anumeha is mowing the lawns for a summer job. For every mowing job, she charges and initial fee of $10 plus a constant fee for e

ach hour of work. Her fee for a 5-hour job, for instance is $35. Let F(t) denote Anumeha's for a single job F (measured in dollars) as a function of the number of hours t it took her to complete it. Write the functions formula
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
8 0

Answer:

F(t) = 10 +5t

Step-by-step explanation:

Income equals the initial fee plus the hours worked times the hourly rate

We know the initial fee = 10

hours = t

hourly rate =r


F(t) = 10 + r*t

We know a 5 hour job is 35 dollars

35 = 10 + r*5

Subtract 10 from each side

35-10 = 10-10 +5r

25 = 5r

Divide by 5

25/5 = 5r/5

5 =r

The hourly rate is 5

F(t) = 10 +5t

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If m1=2x° and m3=3x° what is m1
olga_2 [115]

Answer:

36

Step-by-step explanation:

Using the angle addition postulate

angle 1+angle 2+angle 3=180

Angle 2 is 90 degrees,

Angle 1 is 2x degrees

Angle 3 is 3x degrees

Plug this into equation

2x + 90 +  3x = 180

5x + 90 = 180

5x = 90

x = 18

Plug 18 into 2x

2(18) = 36

5 0
3 years ago
(03.09 MC) Derive the equation of the parabola with a focus at (−2, 4) and a directrix of y = 6. Put the equation in standard fo
Nookie1986 [14]
Check the picture below.

so the focus point is at -2, 4 and the directrix is at y = 6, now, keeping in mind that the vertex is half-way between those two fellows, from 4 to 6, it'd be the y-coordinate of 5, and therefore, the vertex is at -2,5, as you see there in the picture, and the parabola looks like so.  Since the parabola is a vertical one, the squared variable is the "x".

notice the distance "p", is just 1 unit, however, since the parabola is opening downwards, "p" is negative, and thus -1.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
4p(x- h)=(y- k)^2
\\\\
\boxed{4p(y- k)=(x- h)^2}
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ( h, k)\\\\
 p=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=-2\\
k=5\\
p=-1
\end{cases}\implies 4(-1)(y-5)=[x-(-2)]^2
\\\\\\
-4(y-5)=(x+2)^2\implies y-5=-\cfrac{1}{4}(x+2)^2
\\\\\\
y=-\cfrac{1}{4}(x+2)^2+5

5 0
3 years ago
Read 2 more answers
Evaluate the function f(x) = 2x3 - 6x + 1 for f(-2).
erma4kov [3.2K]

Answer:

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Step-by-step explanation:

f(x) = 2 {x}^{3}  - 6x + 1 \\ plugging \: x =  - 2 \\ f( - 2) = 2( { - 2})^{3}  - 6( - 2)+ 1  \\  = 2 \times ( - 8) + 12 + 1 \\  =  - 16 + 13 \\  =  - 3 \\ f( - 2) =  - 3

7 0
4 years ago
Using Pythagorean Theorem what is the square root of the third side ?
IrinaVladis [17]
Pythagorean theorm is a^2+b^2=c^2
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5 0
3 years ago
PLEASE HURRY i really need help with this
Serjik [45]
180-45= 135, the answer is 135
4 0
3 years ago
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