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sashaice [31]
4 years ago
6

The graph below represents Function R

Mathematics
1 answer:
Phoenix [80]4 years ago
4 0

Option A: The rate of change of Function R is less than the rate of change of Function S because \frac{2}{3} is true.

Explanation:

The function S=3x-1

The equation for function R can be determined using the slope formula,

y=mx+b

The y-intercept is the value of y, when x = 0.

Thus, the y-intercept is b=1.

To determine the slope, let us substitute the coordinates (0,1) and (3,3).

Because, the points on the straight line have the same slope.

Thus, we have,

m=\frac{y_2-y_1}{x_2-x_1} \\m=\frac{3-1}{3-0} \\m=\frac{2}{3}

Thus, m=\frac{2}{3} and b=1

Let us substitute these values in the formula y=mx+b, we get,

y=\frac{2}{3} x+1

Hence, the equation of R is y=\frac{2}{3} x+1

The equation of S is y=3x-1

Comparing the slope of these two equations, we have,

\frac{2}{3}

This means that the slope of R is less than the slope of S.

Hence, The rate of change of Function R is less than the rate of change of Function S because \frac{2}{3}

Thus, Option A is true.

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A company has determined that its maximum profit occurs when it sells 10,000units per month. For every 1,000 units more or less
seropon [69]

Answer:

B. 5 |q−10| =35

Step-by-step explanation:

Solution:

let's try to understand the problem clearly.

In this question, we asked to calculate the number units which that company produces so that it's profit is decreased from the maximum profit.

We know that, for 10000 units = company will get maximum profit.

Any value less than or greater than 10000 units will decrease the profit.

and we also know that,

For every 1000 units profit is decreased by $5000.

So if maximum profit is at 10000 units,

Then at 9000 units = it will have profit decreased by 5000 from the maximum

if q = 11000 then profit = Maximum - 5000

But we are asked to calculate the profit decrease of $35000 from the maximum.

it means we need 5000 decreased by 7 times = 10000 +  7000 = 17000 units

So, if company produces 17000 units,

profit will be decreased by 5(7000) = 35000

Finally,

B. is the only equation which satisfies this condition.

B.  5 (q-10) = 35

(q-10) = 7

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5 0
3 years ago
PLZZZ HELP I'LL GIVR U A MEDAL N FAN U
disa [49]
The first option is correct I did this before hope this helps
6 0
4 years ago
Read 2 more answers
Describe the accumulated value a of the sum of money P the principal after two years at annual percent rich are in the decimal f
elena-14-01-66 [18.8K]

In order to calculate the value of t, we can use the given formula with the values P = 6000, A = 2P and i = 11% = 0.11:

\begin{gathered} 2\cdot6000=6000\cdot e^{0.11t}\\ \\ 2=e^{0.11t}\\ \\ \ln2=\ln e^{0.11t}\\ \\ 0.693147=0.11t\\ \\ t=\frac{0.693147}{0.11}=6.3 \end{gathered}

Therefore the time needed is t = 6.3 years.

8 0
2 years ago
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