Answer:
x = 9
y = 13
Step-by-step explanation:
Side-Side-Side or SSS means that if all three sides of one triangle are equal to all three corresponding sides of another triangle, then the two triangles are considered to be congruent (equal).
Therefore, GH = PM ⇒ 7x + 8 = 6y - 7
and, GP = HM ⇒ 8x - 10 = 5y - 3
Rewrite the first expression to make x the subject, then substitute this into the second equation, and solve for y:
GH = PM
⇒ 7x + 8 = 6y - 7
⇒ 7x = 6y - 15
⇒ x = (6/7)y - 15/7
Substituting x = (6/7)y - 15/7 into GP = HM:
GP = HM
⇒ 8x - 10 = 5y - 3
⇒ 8[(6/7)y - 15/7] - 10 = 5y - 3
⇒ (48/7)y - 120/7 - 10 = 5y - 3
⇒ (13/7)y = 169/7
⇒ y = 13
Now we have found a value for y, substitute this into one of the expressions and solve for x:
8x - 10 = 5y - 3
⇒ 8x - 10 = (5 x 13) - 3
⇒ 8x - 10 = 62
⇒ 8x = 72
⇒ x = 9
Start with with original price and find 30% of that price:
30% of 810: (0.30)(810) = 243
Now take that 30% away:
810 - 243 = 567
That's the sale price: $567
Find 30% of the sale price:
30% of 567: (0.30)(567) = 170.10
Now add that 30% on to the sale price:
567 + 1701.0 = 737.10
The final price described is $737.10.
Now we need to relate that final price to the original price:
737.10 ÷ 810 = 0.91
This means that the final price is 91% of the original price.
Answer:
36 m 32 s
Step-by-step explanation:
67 /110 = 0.609 hour
0.609 × 60 minutes = 36.54 minutes
36 minutes + 0.54×60 second
= 36 minutes 32 seconds
T-6=-4
Just simply add 6 to both sides, it will cancel out the -6 and leave T alone, and it will become T=2, There's your answer.
Answer:
x = 10
Step-by-step explanation:
You can try the answers to see which works. (The first one does.)
Or, you can solve for the variable:
Divide by 75
... (1/5)^(x/5) = 3/75 = 1/25
Recognize that 25 = 5^2, so ...
... (1/5)^(x/5) = (1/5)^2
Equating exponents, you have
... x/5 = 2
... x = 10 . . . . . multiply by 5
_____
You can also start by taking logarithms:
... log(75) +(x/5)log(1/5) = log(3)
... (x/5)log(1/5) = log(3) -log(75) = log(3/75) = log(1/25) . . . . simplify the log
... x/5 = log(1/25)/log(1/5) = 2 . . . . . simplify (or evaluate) the log expression
... x = 10 . . . . . multiply by 5
_____
"Equating exponents" is essentially the same as taking logarithms.
