3 years ago

Find the area of the trapezoid.

1 answer:

3 0

The area equation is $A=\frac{a+b}{2} *h$

the trapezoid is actually on its side
so a=10.2
b=12.2
h=12.6

$A=\frac{10.2+12.2}{2} *12.6\\
=\frac{22.4}{2} *12.6\\
=11.2*12.6\\
=141.12\\$

You might be interested in

PLEASE HELP ME!!!!!!! WILL GIVE THANKS AND RATING!!!!!! PLEASEEEEEEEEEEEEEE!!!!!!!

EastWind [94]

2 3/4 * 3.36 / (1 2/5)
=11/4 * 3.36 / (7/5)
= 9.24 / (7/5)
= 9.24 / 1.4
= 6.6

5 0

3 years ago

Hurry and answer please

arlik [135]

It's c (48)

because if you divide all of them its 3

5 0

2 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

7 0

3 years ago

Read 2 more answers

Please help me and the answer is not the first one

Anna11 [10]

I think it’s the second one!!!

5 0

3 years ago

Read 2 more answers

Expand the expression 4(y+z)

Ilia_Sergeevich [38]

Answer: 4y+4z

Step-by-step explanation:

5 0

3 years ago