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4 years ago

Factor using given common factor. Assume all variables represent real positive numbers. (Y^-5)-(3y^-3); y^-5

Mathematics

1 answer:

stellarik [79]4 years ago

6 0

Divide the expression by the factor y^-5
y^-5(1 - 3y^2)

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What is the equation of the line that passes through the point 4, -6 and has a slope of -3

zheka24 [161]

Y = mx + b. Use this equation for most linear functions. Enter the information that is given to you.
$- 6 = - 3(4) + b$
Multiply the -3 and 4 to get 12.
$-6 = - 12 + b$
Now divide the -12 from both sides.
$\frac{ - 6}{ - 12} = \frac{ - 12}{ - 12} + b$
-12 cancels out on the right side and your left with
$- \frac {1}{2} = b$
Now re-enter the info back into the formula.
$y = - 3x - \frac{1}{2}$
Then you've got your formula

4 0

3 years ago

26) In triangle ABC, if AB-BC and B

MariettaO [177]

Answer:

55degrees

Step-by-step explanation:

Let the other angles of the triangle are x, x degrees. Since the sum of angles in a triangle is 180degrees, hence;

<A + <B+ <C = 180

x + 70 + x = 180

2x+70 = 180

2x = 180 - 70

2x = 110

x = 110/2

x = 55

SInce <A is equal to x, hence <A is 55degrees

3 0

3 years ago

PLEASEPLEASE ANSWER IM BEGGING JSJDJDJ

Rama09 [41]

Answer: x=15

Explanation: you can set 2x+100 = 5x+55 because they are corresponding interior angles.

Work:
2x+100 = 5x+55
2x+100-5x = 55
2x-5x = 55-100
-3x = -45
divide by -3 to cancel the negative and get x by itself
x = 15

Hope this helped! :)

5 0

3 years ago

F(x) = -4x2 + 10<br> Find f(-2)

Veronika [31]

Answer:

f(-2) = -6

Step-by-step explanation:

In the expression, to get f(-2);

we simply substitute the value of x with -2

We have this as;

f(-2) = -4(-2)^2 + 10

f(-2) = -4(4) + 10

f(-2) = -16 + 10

f(-2) = -6

3 0

3 years ago

Find the indefinite integral by using the substitution x = 4 sec(θ). (Use C for the constant of integration.) x2 − 16 x d

guapka [62]

Answer:

$\frac{x^2-16}{2} + 16ln\frac{4}{x} +16C$

Step-by-step explanation:

Given the indefinite integral $\int\limits{\frac{x^2-16}{x} } \, dx$ , using the substitute

x = 4 sec(θ)...1

The integral can be calculated as thus;

First let us diffrentiate the substitute function with respect to θ

dx/dθ = 4secθtanθ

dx = 4secθtanθdθ... 2

Substituting equation 1 and 2 into the integral function we will have;

$\int\limits{\frac{(4sec \theta)^2-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{16sec^2 \theta-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{(16(sec^2 \theta-1)}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\from \ trig \ identity,\ sec^2 \theta - 1 = tan^\theta\\\\\int\limits{\frac{16 tan^2 \theta}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\\int\limits 16 tan^3 \theta d \theta\\\\$

Find the remaining solution in the attachment.

3 0

3 years ago