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valina [46]
3 years ago
12

Which equation would help determine the cost of 2 folders?

Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0
The answer to your question would be b.
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Its 3:49, school is almost done, so answer one question plss
mylen [45]

Answer:

The answer is D.

Step-by-step explanation:

Well since there are 4 values calculated then 2 would be above the  mean because plus the 2 values above the mean. I don't know if it makes since though.

6 0
2 years ago
Please help. I don’t know the answer.
atroni [7]
(y^12)/5

9/45=1/5
x^5/x^5=1
y^16/y^4=y^12
4 0
2 years ago
Read 2 more answers
Jill had $125 to spend at the mall. She spent 27% of that money on a pair of shoes. Jill spent $___ on the shoes.
zaharov [31]
You need to find what 27% of $125 is.
To find a percent of a number, multiply the percent by the number.

27% of $125 =

= 27% * $125

= 0.27 * $125

= $33.75

Answer: Jill spent $33.75 on the shoes.
4 0
3 years ago
Help me with this question <br> Please I need help
34kurt

Answer:

384 cm²

Step-by-step explanation:

The shape of the figure given in the question above is simply a combined shape of parallelogram and rectangle.

To obtain the area of the figure, we shall determine the area of the parallelogram and rectangle. This can be obtained as follow:

For parallelogram:

Height (H) = 7.5 cm

Base (B) = 24 cm

Area of parallelogram (A₁) =?

A₁ = B × H

A₁ = 24 × 7.5

A₁ = 180 cm²

For rectangle:

Length (L) = 24 cm

Width (W) = 8.5 cm

Area of rectangle (A₂) =?

A₂ = L × W

A₂ = 24 × 8.5

A₂ = 204 cm²

Finally, we shall determine the area of the shape.

Area of parallelogram (A₁) = 180 cm²

Area of rectangle (A₂) = 204 cm²

Area of figure (A)

A = A₁ + A₂

A = 180 + 204

A = 384 cm²

Therefore, the area of the figure is 384 cm²

3 0
2 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 5 ftys along
Sever21 [200]

25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path. This can be obtained by considering this as a right angled triangle.

<h3>How fast is the tip of his shadow moving?</h3>

Let x be the length between man and the pole, y be the distance between the tip of the shadow and the pole.

Then y - x will be the length between the man and the tip of the shadow.

Since two triangles are similar, we can write

\frac{y-x}{y} =\frac{6}{15}

⇒15(y-x) = 6y

15 y - 15 x = 6y

9y = 15x

y = 15/9 x

y = 5/3 x

Differentiate both sides

dy/dt = 5/3 dx/dt

dy/dt is the speed of the tip of the shadow, dx/dt is the speed of the man.

Given that dx/dt = 5 ft/s

Thus dy/dt = (5/3)×5 ft/s

dy/dt = 25/3 ft/s

Hence 25/3 ft/s is speed of the tip of his shadow moving when a man is 40 ft from the pole given that a street light is mounted at the top of a 15-ft-tall pole and the man is 6 ft tall who is walking away from the pole with a speed of 5 ft/s along a straight path.

Learn more about similar triangles here:

brainly.com/question/8691470

#SPJ4

3 0
1 year ago
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