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Dmitrij [34]
2 years ago
15

I WILL GIVE BRAINLEST

Mathematics
1 answer:
Allushta [10]2 years ago
6 0

Answer:

41.86 is the right answer

Step-by-step explanation:

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try number 4 I thinks its that one or number 1

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Solve the compound inequality.<br><br> 9 – 4x ≥ 5 or 4(–1 + x) – 6 ≥ 2
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X ≤ 1 and x ≥ 3
Hope this helps :)
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I need help with this Algebra 1 Study Guide. It has 5 questions . This has many hard questions so to you people that like a chal
scoundrel [369]
1. Rational numbers can be written as a ratio (fraction)
Whole numbers are rational. 5 = 5/1, for example.
Square roots are NOT rational.  Example: √3
However, square roots of square numbers can be simplified, and are therefore rational. <span>√4 = 2, rational.</span>

√4 + <span>√16 = 2 + 4 = 6. rational
</span>√5 + √36...<span> irrational
</span>√9 + <span>√24... irrational
</span>2 × <span>√4 = 2 × 2 = 4. rational
</span>√49 × <span>√81 = 7 × 9 = 63. rational
</span>3√12... irrational

2. n^\frac12=\sqrtn
9^\frac32=9^3\times\frac12=\sqrt{9^3}=\sqrt{729}=29

3. \frac{n^a}{n^b}=n^{a-b}

\frac{a^\frac13}{a^\frac14}=a^{\frac13-\frac14}=a^{\frac{1}{12}}

4. n^\frac1x=\sqrt[x]n

\sqrt[3]{m^2n^5}=m^{\frac23}n^{\frac53}

5. \sqrt{a}\times\sqrt{b}=\sqrt{ab}

\sqrt{3}\times\sqrt{12}=\sqrt{3\times12}=\sqrt{36}=6

A, since neither 3 nor 12 is a square but we end up with 6.
5 0
3 years ago
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