Answer:
A, dilation by a scale factor of 2 and a reflection across the y-axis
Step-by-step explanation:
Answer:
- A. segment A double prime B double prime = segment AB over 2
Step-by-step explanation:
<u>Triangle ABC with coordinates of:</u>
- A = (-3, 3), B = (1, -3), C = (-3, -3)
<u>Translation (x + 2, y + 0), coordinates will be:</u>
- A' = (-1, 3), B = ( 3, -3), C = (-1, -3)
<u>Dilation by a scale factor of 1/2 from the origin, coordinates will be:</u>
- A'' = (-0.5, 1.5), B'' = (1.5, -1.5), C= (-0.5, -1.5)
<u>Let's find the length of AB and A''B'' using distance formula</u>
- d = √(x2-x1)² + (y2 - y1)²
- AB = √(1-(-3))² + (-3 -3)² = √4²+6² = √16+36 = √52 = 2√13
- A''B'' = √(1.5 - (-0.5)) + (-1.5 - 1.5)² = √2²+3² = √13
<u>We see that </u>
<u>Now the answer options:</u>
A. segment A double prime B double prime = segment AB over 2
B. segment AB = segment A double prime B double prime over 2
- Incorrect. Should be AB = A''B''*2
C. segment AB over segment A double prime B double prime = one half
- Incorrect. Should be AB/A''B'' = 2
D. segment A double prime B double prime over segment AB = 2
- Incorrect. Should be A''B''/AB = 1/2
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Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
