Diane keeps all of her toys on a shelf. The shelf is 24" long and 7" wide. If the wdith the shelf is doubled, what would happen
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The number of tiles needed to cover the surface area of the box excluding the bottom is: 1,046 tiles.
<h3>What is the Surface Area of a Box?</h3>The surface area of a box is the area surrounding all its faces. A box has 6 rectangular faces. Therefore, the total surface area of the box equals the sum of all 6 rectangular faces.
<h3>What is the Surface Area of a Box?</h3>SA = 2(lw + lh + hw), where:
- l = length
- w = width
- h = height of the box
The image attached below shows the box Dmitri wants to cover. Since the bottom of the box would be excluded, therefore:
The surface area to be covered = surface area of the box - area of the bottom rectangular face
The surface area to be covered = 2(lw + lh + hw) - (l)(w)
l = 26
w = 15
h = 8
Substitute
The surface area to be covered = 2(l×w + lh + hw) - (l)(w) = 2·(15·26+8·26+8·15) - (26)(15) =
The surface area to be covered = 1436 - 390 = 1,046 cm
Area of one tile = 1 cm square
Number of tiles needed = 1,046/1
Number of tiles needed = 1,046 tiles.
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We know,
sin(x) and cos(x) have minimum value equal to -1 and maximum value is 1.
Maximum value of sin(x) is 1
So we replace sin by 1 in our given equation
When we replace sin by 1 we will get
y= -2+5 = 3
So maximum value is 3