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Alex Ar [27]
3 years ago
8

The circle below is centered at (3 1) and has a radius of 2 what is its equation

Mathematics
1 answer:
Dominik [7]3 years ago
7 0

Answer:

(x-3)^2 + (y-1)^2 = 4

Step-by-step explanation:

The equation of a circle is usually written in the form

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

The center is at the origin so (h,k) = (3,1) and  the radius is 2 so r=2

(x-3)^2 + (y-1)^2 = 2^2

(x-3)^2 + (y-1)^2 = 4

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if the length of a rectangle is decreased by 2cm and the width is increased by 6 cm the result will be a square the area of this
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<h3>How to determine the rectangle area?</h3>

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So, the length of the square would be:

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The areas are then calculated as:

Rectangle = xy

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