Question

The circle below is centered at (3 1) and has a radius of 2 what is its equation

Answer 1

Answer:

(x-3)^2 + (y-1)^2 = 4

Step-by-step explanation:

The equation of a circle is usually written in the form

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

The center is at the origin so (h,k) = (3,1) and  the radius is 2 so r=2

(x-3)^2 + (y-1)^2 = 2^2

(x-3)^2 + (y-1)^2 = 4