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wel
3 years ago
13

What is the pair of angles called.

Mathematics
1 answer:
vodka [1.7K]3 years ago
4 0
The answer is D. Trust me.
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An architect is designing a house for the Frazier family. The Fraziers have asked that the cost of
PolarNik [594]

Answer:

║x - 175,000║≤ 20,000

Step-by-step explanation:

Let x be the amount the Fraziers are willing to pay. Since the house costs $175,000 and they are willing to deviate from this price no more than $20,000, so x =  $175,000 ± $20,000.

So, x - 175,000 = ± 20000

║x - 175,000║= 20,000

But we require  

║x - 175,000║≤ 20,000

which is our required open sentence.

8 0
3 years ago
Help within 10 min pleeeeeeeeeease
sineoko [7]
The answer should be 75
4 0
2 years ago
Read 2 more answers
4/9×5/8×9/25 I want to the answer for this question
wel

Answer:

0.1 ....................

3 0
3 years ago
Spiral Review
Svetllana [295]

Answer:

Your answer is C

Step-by-step explanation:

0.5 = Five tenths

and

0.05 = five hundredths

This is because 0.5 is like 50 cents and 0.05 is like 5 cents

The rest are wrong because A: 0.05 simply can't be bigger than 0.5

B is wrong because they aren't equal to each other

and D is wrong because 0.05 + 0.5 = 0.55

  • (\) QueTooOfficial (/)
3 0
3 years ago
Read 2 more answers
One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
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