Question

Middletown Street and Kensington Avenue intersect. If Middletown Street is 5.2 meters wide and Kensington Avenue is 7.6 meters wide, what is the distance between two opposite corners of the intersection? If necessary, round to the nearest tenth.

Answer 1

Answer: The distance between two opposite corners of the intersection is 9.2 meters.

Explanation:

Since we have given that

Width of the Middletown Street = 5.2 m

Width of Kensington Street = 7.6 m

When they intersect each other then we have to find  the distance between two opposite corners of the intersection,

Since they formed a right angled triangle shown in the figure below:

So, we can apply "Pythagorus Theorem"

$H^2=B^2+P^2\\\\H^2=5.2^2+7.6^2\\\\H^2=27.04+57.76\\\\H^2=84.8\\\\H=\sqrt{84.8}\\\\H=9.2\ m$

Hence, the distance between two opposite corners of the intersection is 9.2 meters.