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Jobisdone [24]
3 years ago
8

GEOMETRY HELP!!

Mathematics
1 answer:
Vlada [557]3 years ago
5 0

Answer:

0

Step-by-step explanation:

To find the coordinate of the midpoint of segment QB, first, find the distance from Q to B.

QB = |4 - 8| = |-4| = 4

The coordinate of the midpoint of QB would be at ½ the distance of QB (½*4 = 2).

Therefore, coordinate of the midpoint of QB = the coordinate of Q + 2 = 4 + 2 = 6

OR

Coordinate of B - 2 = 8 - 2 = 6

Coordinate of the midpoint of QB = 6

Coordinate of W = -8

Coordinate of A = 0

distance from W to A (WA) = |-8 - 0| = |-8| = 8

The coordinate of the midpoint of WA would be at ½ the distance of WA = ½*8 = 4.

Therefore, coordinate of the midpoint of WA = the coordinate of W + 4 = -8 + 4 = -4

Or

Coordinate of A - 4 = 0 - 4 = -4

Coordinate of the midpoint of WA = -4

Now, let's find the midpoint between the two new coordinates we have found, which are -4 and 4

Distance of the segment formed by coordinate -4 and 4 = |-4 - 4| = |-8| = 8

Midpoint = ½*8 = 4

Coordinate of the midpoint = -4 + 4 = 0

Or

4 - 4 = 0

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Answer:

t is approximately 10.41 seconds

Step-by-step explanation:

s = 16t^2

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sqrt(1734/16) = sqrt(t^2)

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3 years ago
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Step-by-step explanation:

All you have to do is multiply.

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2 years ago
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui
Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

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Therefore, \frac{AB}{EC}=\frac{BD}{CD}

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Differentiate w.r.t t

x\frac{dy}{dt}+y\frac{dx}{dt}=0

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\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}

When the man is 4 m from  the building

Then, we have x=12-4=8 m

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Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0
3 years ago
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