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3 years ago

Which is the solution to 8^x=3^x+2

Mathematics

1 answer:

beks73 [17]3 years ago

6 0

Answer:

A. 2.2402

Step-by-step explanation:

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BRAINLIEST ANSWER!! ASAP 3(x+1)+6=-9 PLEASE EXPLAIN HOW YOU GOT THE ANSWER

Kryger [21]

Answer:

x=-6

Step-by-step explanation:

use distributive property on the () and times x and 1 by three

then you subtract 6 from both sides

then subtract three from both sides

then divide both sides by 3

your work would look like this:

3(x+1)+6=-9

3x+3+6=-9

3x+3=-15

3x=-18

x=-6

Hope this helps!

8 0

3 years ago

Read 2 more answers

The shortest side of a polygon of area 196 sq. in. is 4 in. long. Find the area of a similar polygon whose shortest side is 8 in

fenix001 [56]

The correct answer is: " 784 in² " .
_________________________________________
                  {or; write as: " 784 sq. inches " .}.
_________________________________________
      When the side is doubled (in this case, 4 is doubled; 4 * 2 = 8} ; the area is increased by 2² times; that is, by 4 times; so, the area is:
    (196 sq. in) * 4 =   784 sq inches .
_________________________________________

7 0

3 years ago

Read 2 more answers

New York City is located about 40˚ north of the equator. If Earth's radius is about 4000 miles, approximately how many miles sou

qwelly [4]

Answer:

The answer is "2793 miles"

Step-by-step explanation:

In this firstly we convert degrees to radians, which can be defined as follows:

$\to \theta =\frac{40^{\circ} \times \pi }{180^{\circ}}$

$=\frac{ 2\pi }{9}$

Now calculating the distance:

$=\frac{2\pi }{9} \times 4000\\\\= \frac{8000 \pi }{9}$

$=\frac{8000\times 3.14 }{9}\\\\ = \frac{25120}{9}\\\\=2793 \ miles$

4 0

3 years ago

Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

⇒ α = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0

3 years ago

Solve for y. pls help me

lesya [120]

Answer:

y should I slove for 'y'

if there's no Y

7 0

3 years ago