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otez555 [7]
3 years ago
13

Are the lines shown below parallel? Explain

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer:

C. No, the slopes are not the same

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(Prove) The angle subtended by an arc at the center is double the angle subtended by it at any
Pavlova-9 [17]

Answer:

The angle subtended by an arc at the center is double the angle subtended by it at any  point on the remaining part of the circle.

Step-by-step explanation:

Let us consider the image attached.

Center of circle be O.

Arc AB subtends the angle \angle APB on the circle and \angle AOB on the center of the circle.

To prove:

\angle AOB = 2 \times \angle APB

Proof:

In \triangle PAO: AO and PO are radius of the circles so AO = PO

And angles opposite to equal sides of a triangle are also equal in a triangle.

So, \angle PAO = \angle OPA

Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

\angle AOQ = \angle PAO + \angle OPA=2 \times \angle APO .... (1)

Similarly,

In \triangle PBO: BO and PO are radius of the circles so BO = PO

And angles opposite to equal sides of a triangle are also equal in a triangle.

So, \angle PBO = \angle OPB

Using external angle property, that external angle is equal to sum of two opposite internal angles of a triangle.

\angle BOQ = \angle PBO + \angle OPB=2 \times \angle BPO .... (2)

Now, we can see that:

\angle AOB = \angle AOQ+\angle BOQ

Using equations (1) and (2):

\angle AOB = 2\angle APO+2\angle BPO\\\angle AOB = 2(\angle APO+\angle BPO)\\\bold{\angle AOB = 2(\angle APB)}

Hence, proved.

4 0
3 years ago
16. Solve for x<br> 20°<br> 7x+7
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Answer:

any figure or more info given??

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3 years ago
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