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harkovskaia [24]
3 years ago
7

Between which two consecutive integers is the fraction 72/11

Mathematics
1 answer:
Shalnov [3]3 years ago
3 0

Answer:

6 and 7

Step-by-step explanation: 72/11 = 6.5454545454545454 etc

6.54545454 is in between 6 and 7

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Multiply.<br><br> 1/4 x 32 =
Solnce55 [7]
Simply change 1/4 to a decimal 
1/4 = 0.25 
now we can multiply 0.25 and 32
lets do the math:)
0.25 x 32 = 8
your answer = 8 

When in doubt, eat a pineapple :)




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2 years ago
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Write the inequality represented by the graph below
olchik [2.2K]

Answer:

y≥3x-1

Step-by-step explanation:

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b=y intercept

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5 0
3 years ago
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Use the graph that shows the solution to
Luda [366]

Answer:

The solution for f(x) = g(x) are;

x = 1 and x = -1

Step-by-step explanation:

The given equations for the functions, g(x) are;

f(x) = \dfrac{1 + 2\cdot x}{x}

g(x) = 2 + x

The solution for f(x) = g(x), is given by equating the equations of the two functions as follows;

When f(x) = g(x), we have;

\dfrac{1 + 2\cdot x}{x} = 2 + x

By cross multiplication, we have;

1 + 2·x = x × (2 + x) = 2·x + x²

∴ x² + 2·x - 2·x - 1 = 0

x² - 1 = 0

(x - 1)·(x + 1) = 0

x = 1, or x = -1

f(x) = g(x) = 2 + 1 = 3, or 2 - 1 = 1

Therefore, the solution for f(x) = g(x) are;

f(x) = g(x) = 3 or 1 where x = 1 and x = -1.

6 0
2 years ago
Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

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3 years ago
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PLEASE HELP ME PLEASE !!!
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Answer:

i need more information about the question... i suggest googleing it

Step-by-step explanation:

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