<h2>
Answer:</h2>
<h3>
<em>x=45degrees</em></h3>
<h2>
Step-by-step explanation:</h2>
Let the angle to be solved be x
Let the supplement/compliment by y
x+y=90 Complimentary angles add up to 90 degrees.
x+3y=180 Supplementary angles add up to 180 degrees, the other angle is thrice the other compliment.
Evaluating this as a system:
x+y=90 Isolate x:
x=90−y Input into the other equation:
(90−y)+3y=180 Combine like terms, isolate y and its coefficients:
2y=90 Isolate y
y=45 Input into the first equation:
x+45=90 Isolate x:
x=45degrees
48 + (2*13) / 110
PE(MD)(AS)
2 * 13 = 26
48 + 26 / 110
26 / 110 = 0.236..
Rounded = 0.24
48 + 0.24 = 48.24….
??????…
Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let 
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.
![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)
So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Answer:
Step-by-step explanation:
Given:
Substitution can be used to find the value of 
:
Hope this helps :)
Answer:
6250
Step-by-step explanation:
Hope the answer is correct.
