I have returned!
36 can technically be either A or B, although A works better. The workers are trying to see which type of vegetables sell better, and it’s easier to see which bar is taller rather than which slice is bigger.
37 would be the median, or the middle of all the values. The median is 30 (two smaller and two bigger values), while the range is 27 (32-5, range of values), the mode is 5 (the value that occurs the most), and the mean is 20.6 (average of all values). The median is the only value larger than 30, so this would be the best one to tell his parents.
Answer:
B) -125a^11
Step-by-step explanation:
(-5a^2)^3·a^5 = (-5)^3·a^6·a^5
= (-5)^3·a^(2·3)·a^5
= (-5)^3·a^6·a^5
= -125·a^(6+5)
= -125·a^11 . . . . matches choice B
_____
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
2(4x - 9) =
2 * 4x - 2 * 9 =
8x - 18
Hope this helps!!
~Kiwi
Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
Because tens numbers are easier to work with. If you have the problem 9+3, you can take one out of three and add it to the nine to get 10+2.