All categories

3 years ago

What is the equation for the graph in slope-intercept?

Mathematics

1 answer:

Julli [10]3 years ago

6 0

Answer:

y=7/4x+7

Step-by-step explanation:

You might be interested in

Choose the function whose graph is given by:

adoni [48]

Answer: y = 0.5cos(x), choice A

The parent function y = cos(x) follows this same basic pattern of the curve shown, but it starts off at (0,1) as its highest point. This graph has its highest point to be half as high, so we multiply by 1/2 or 0.5

3 0

3 years ago

Read 2 more answers

Geometry question, any help is appreciated

kodGreya [7K]

Answer:

Hence, the ratios are given by 5:7, 25:49, 125:343.

Step-by-step explanation:

We are given two spheres such that:

Volume of small sphere $V_{s}$ = 250 $yd^{3}$

Volume of large sphere $V_{l}$ = 686 $yd^{3}$ .

Then the ratio of volume = 250 : 686 = 125 : 343.

Since, the volume of a sphere = $\frac{4 \pi \times r^{3}}{3}$ , this gives us that the ratio of the radius = ∛ $V_{s}$ : ∛ $V_{l}$

i.e. The ratio of the radius = ∛125 : ∛343 = 5 : 7.

Further, as the surface area of a sphere = $4 \pi \times r^{2}$ , this gives us that the ratioof surface area = $r_{s} ^{2}$ : $r_{l} ^{2}$

i.e The ratio of the surface area = $5^{2}$ : $7^{2}$ = 25 : 49

So, the ratio of the surface areas = 25 : 49.

Hence, the ratios are given by 5:7, 25:49, 125:343.

4 0

2 years ago

Read 2 more answers

a Textbook weighs 2.5 pounds. how many kilograms does the textbook weigh? round your answer to the nearest tenth of a pound. one

Rzqust [24]

If you round it to the nearest pound it is 1.1 kg
2.5/2.2 = 1.13....

3 0

3 years ago

Read 2 more answers

Triangle JKL has vertices J(-4, -1), K(0, 4), and L(-4, -2). Graph The triangle and it’s image after a dilation with a scale fac

Dafna1 [17]

Answer:

J(-2, -0.5), K(0, 2), L(-2, -1)

Step-by-step explanation:

5 0

2 years ago

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago