How accurate the information is.
Known Variables:
Δy = 1.5 m
v0 = 30m/s at 60° above the horizontal.
t = 4.0 s
a. vfy = v0y + at
0 = 30sin(60) + (-9.8)t
-25.98 = -9.8t
t = 2.65.
4-2.65 = 1.35s.
Δy = v0yt + at^2/2
Δy = 25.98(2.65) + (-9.8)(2.65)^2/2
Δy = 34.44 m
1.5 + 34.44 = 35.94 m.
Δy = v0t + at^2/2
Δy = (-9.8)(1.35)^2/2
Δy = -8.93.
35.94 - 8.93 = 27.01 m.
b. vfy = v0y + at
0 = 30sin(60) + (-9.8)t
-25.98 = -9.8t
t = 2.65.
Δy = v0yt + at^2/2
Δy = 25.98(2.65) + (-9.8)(2.65)^2/2
Δy = 34.44 m
1.5 + 34.44 = 35.94 m.
vfy = v0y + at
vfy = (-9.8)(1.35)
vfy = -13.23 m/s.
I might have gone wrong somewhere so please check my answer! Cheers!
Explanation:
Well to be honest, American accents to me sound like exaggerated English. When I say that I mean that there is a lot of emphasis on their words, (Considering the fact that their way of speaking isn't proper). I guess I could say American accents sound hard with their broken English. (no offense)
~person who answered the question ~
