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Anna007 [38]
3 years ago
12

Triangle PQR is transformed to the similar figure P'Q'R'. What is the scale factor of dilation? 1/2,1/3,1/4,1/5

Mathematics
1 answer:
Ratling [72]3 years ago
6 0

The answer is 1/2 and that is because if you calculate how long a segment is, lets say PQ then thats 8-4 and you get 4. and then P'Q' thats 4-2 which equals 2 and that is 1/2 of 4

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grandymaker [24]
I think it would be the third option.
8 0
3 years ago
Graph the equation shown below by transforming the given graph of the parent<br> function.
zheka24 [161]

Answer:

Step-by-step explanation:

The graph shown is f(x)=y=|x|

The required graph is g(x) = |x|-3 = f(x) -3

In general, the graph of f(x)-3 is 3 units below f(x), and has the same shape.

See attached graph. y=f(x)=|x| in blue, f(x)-3 = |x|-3 in red.

7 0
2 years ago
james and his sister save money for a trip to the water park. james has saved half the amount of money as his sister has saved.
valina [46]

Answer:

money saved by james = 30/2 = 15

equation used

money with James  = 3/4 (money with sister)

x/2 + 30 =3/4( x + 30 )

Step-by-step explanation:

Let money saved by sister be x

given

James has saved half the amount of money as his sister has saved.

Money saved by James = x/2

Total money saved by both of them = x + x/2

If they both save 30 more

Then

money with sister = x + 30

money with james = x/2 + 30

given that If they both save 30 more, james will have saved 3/4 as much as her sister

thus,

money with james  = 3/4 (money with sister)

x/2 + 30 =3/4( x + 30 )

=> 4(x+30*2) /2 = 3x+90

=> 2x + 120 = 3x + 90

=> 3x-2x = 120-90

=> x = 30

Thus,

money saved by james = 30/2 = 15

equation used

money with james  = 3/4 (money with sister)

x/2 + 30 =3/4( x + 30 )

4 0
2 years ago
Solve for u.<br> 2 = 10 – 2u<br> u =
Bingel [31]
When solving for you it would equal 6 so U=6 hope that helps
8 0
3 years ago
Read 2 more answers
Will give brainlyest
faust18 [17]

Answer: (1) 42%, (2) 60%, (3) 75%.


Step-by-step explanation: The calculations are as follows

(1) Given that

P(A) = 0.70,  P(B) = 0.25  and P(A and B) = 0.30 ≠ 0. So, the conditional probability of even B when event A has already occured is given by

P(B/A)=\dfrac{p(B\cap A)}{P(A)}=\dfrac{0.30}{0.70}=0.42.

Therefore, the answer is 42%. Also, since the intersection of A and B is not a null set, so these events are dependent events.

(2) Given that

P(A) = 0.40,  P(B) = 0.60  and P(A and B) = 0.24 ≠ 0. So, the conditional probability of even B when event A has already occured is given by

P(B/A)=\dfrac{p(B\cap A)}{P(A)}=\dfrac{0.24}{0.40}=0.60.

Therefore, the answer is 60%. Also, since the intersection of A and B is not a null set, so these events are dependent events.

(3) Given that

P(A) = 0.33,  P(B) = 0.50  and P(A and B) = 0.25 ≠ 0. So, the conditional probability of even B when event A has already occured is given by

P(B/A)=\dfrac{p(B\cap A)}{P(A)}=\dfrac{0.25}{0.33}=0.75.

Therefore, the answer is 75%. Also, since the intersection of A and B is not a null set, so these events are dependent events.

Thus, the answers are 42%, 602% and 75%.

8 0
3 years ago
Read 2 more answers
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