To find the product of two digit number and a 1 digit number you can multiply the tens multiply the ones and find of each

A garden snail traveled 1⁄40 of a mile in 1⁄2 an hour. What was the speed of the snail?

Ratling [72]

1/40 in 30 mins = 2/40 in 1 hour

2/40= 0.05 miles per hour

7 0

2 years ago

Round of 1,546 to the nearest thousands

EleoNora [17]

Answer:

1,546 ≈ 2,000

Hope this helps :)

1. To round to nearest thousands, first look at the hundreds place if the number is 1,2,3,4 then round down. If the number is 5,6,7,8,9 then round up.

4 0

1 year ago

If you vertically compress the absolute value parent function ?? What is the equation of the new function

Bumek [7]

Answer: Choice A -- f(x) = (1/3)*|x|

============================================

The input of a function is x and the output is y = f(x)

To vertically compress a function, we will multiply the y value by some fraction smaller than 1. This is so that the y coordinates are a fraction of what they once were.

In this case, we multiply y by 1/3 so that something that has a y coordinate of y = 81 becomes y = 27 (divide by 3)

So we have y = f(x) become (1/3)*y = (1/3)*f(x) = (1/3)*|x|

4 0

3 years ago

If a/b = 2 /5, b/c = 3 /8, a/c =??

scoray [572]

Answer:

3/20

Step-by-step explanation:

By question it's given that ,

$\implies \dfrac{a}{b}=\dfrac{2}{5}$

$\implies \dfrac{b}{c}=\dfrac{3}{8}$

And we need to find out the value of a/c .For that Multiply both of them , we have ;

$\implies \dfrac{a}{b} \times\dfrac{b}{c}=\dfrac{2}{5}\times \dfrac{3}{8} \\\\\implies \dfrac{a}{c}= \dfrac{3}{20}$

Hence the required answer is 3/20 .

8 0

2 years ago

Expres each of the folowing as a single matrix.

Elden [556K]

Answer:

$\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

Step-by-step explanation:

If you have two matrices:

$A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}a+e&b+f\\c+g&d+h\end{array}\right]$

We have:

$A=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]\\and\\B=\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]$

And we need to express as a single matrix:

$A+B=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6+(-2)&-3+8\\10+3&-1+(-12)\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6-2&5\\13&-1-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

The answer is:

$\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

It is expressed as a single matrix.

8 0

3 years ago