Question

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
A). (tan(x) − 4)(9 sin^2(x) − 1) = 0

B). 3 sin(2x) − 4 sin(x) = 0

Answer 1

Answer:

Step-by-step explanation:

A)$(tanx-4)(9sin^2x-1)=0$

$9sin^2x-1=0\\\\sin^2x=\frac{1}{9} sinx=\frac{1}{3}$ or $sinx=\frac{-1}{3}$

OR    $tanx=4$

B)

$3sin2x=3.2.sinx.cosx\\\\6.sinx.cosx-4.sinx= 2sinx.(3cosx-2)=0\\\\3.cosx=2 cosx=\frac{2}{3}$