All categories

3 years ago

Lina has 12 coins in her purse. D of them are dimes and the rest are quarters.

Mathematics

1 answer:

tester [92]3 years ago

7 0

Answer:

we need more info but 11 q and 1 dime or 12 q and 0 dime

Step-by-step explanation:

Sorry need more info

You might be interested in

At a certain college, there were 600 science majors, 300 engineering majors, and 800 business majors. If one student was selecte

atroni [7]

3/17 should be the answer.

3 0

2 years ago

Read 2 more answers

Which equation best describes the same line as y - 6 = -4(x+1)

Kobotan [32]

Answer:

y - 6 = -4(x+1) is equivalent to equation C: y = -4x + 2

Step-by-step explanation:

Solve the given y - 6 = -4(x+1) for y and remove the parentheses shown:

y - 6 = -4(x+1) becomes

y = -4(x + 1) + 6, or

y = -4x - 4 + 6, or

y = -4x + 2 This is equivalent to equation C.

7 0

3 years ago

Order from Least to Greatest: 1/4 -0.8 0.5 -1.2

Shkiper50 [21]

Answer:

-1.2,-0.8,1/4,0.5

Step-by-step explanation:

hope this helps :D

3 0

2 years ago

What is -138>-6(6b-7)

sertanlavr [38]

First you distribute the six -138>-36b+42 Then you subtract 42 -180>-36b Next, you divide by -36 and since you are dividing by a negative, you turn the sign around 5

6 0

3 years ago

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago