3. The first four terms of a sequence are:
2 answers:
Step-by-step explanation:
tn=n(n+1)(2n+1)
t23=23(23+1)(2*23+1)
t23=36754
Answer:
The 23rd term is 2806.
Step-by-step explanation:
The other answerer has used the formula but i'm answering from the assumption that T1 to T4 are correct.
Each term is the sum of n terms of an arithmetic series with first term a1 = 12 and common difference d = 10.
Sum of n terms = (n/2)[2a1 + d(n - 1)]
So the sum of 23 terms =
= 23/2 (2*12 + 10 * 22)
= 11.5 * 244
= 2806.
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