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Grace [21]
3 years ago
13

3. The first four terms of a sequence are:

Mathematics
2 answers:
iren2701 [21]3 years ago
3 0

Step-by-step explanation:

tn=n(n+1)(2n+1)

t23=23(23+1)(2*23+1)

t23=36754

tatiyna3 years ago
3 0

Answer:

The 23rd term is 2806.

Step-by-step explanation:

The other answerer has used the formula but i'm answering from the assumption that T1 to T4 are correct.

Each term is the sum of n terms of an arithmetic series with first term a1 = 12 and common difference d = 10.

Sum of n terms = (n/2)[2a1  + d(n - 1)]

So the sum of 23 terms =

= 23/2 (2*12 + 10 * 22)

= 11.5 * 244

= 2806.

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Suppose that the position of one particle at time is given by x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π and the position of a second p
Mashcka [7]

Answer:

there is no collision between the particles

Step-by-step explanation:

for the first particle

x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π

for the second particle

x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π

then for the collision

x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t  

y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t  = 2 cos t →(1/3) = 2

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6 0
3 years ago
What -4 times 7 on a number line
Julli [10]

Answer:

-28

Step-by-step explanation:

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6 0
3 years ago
Mrs. Pascal has a candy jar that contains 5 Jolly Ranchers and 13 jawbreakers. Solve each of the following problems and explain
ZanzabumX [31]

Answer:

260 jawbreakers

Step-by-step explanation:

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8 0
3 years ago
a horse is shown in the scale drawing the height of the horse in the drawing is 4.5 inches the scale that maps the drawing to th
Radda [10]
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6 0
3 years ago
Machine A working alone can complete a job in 3 1/2 hours. Machine B working alone can do the same job in 4 2/3 hours. How long
SIZIF [17.4K]

Answer:

B) 2 hours

Step-by-step explanation:

If machine  A complete a job in 3 1/2 hours or 7/2 of an hour

means that in one hour finished 1÷ 7/2     or  2/7

If machine  B complete a job in 4 2/3 hours or  14/3 of an hour

means that in one hour finished 1÷ 14/3    or  3/14 of an hour

Then the two machines working together in one hour will make

2/7 + 3/14    =  (4 + 3)/ 14

or   7/14   = 1/2

half of the job. Therefore these two machines working together will take two hours

5 0
4 years ago
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