Help me plzzz??? Anyone!!!

Geometry Proof - Thanks in advance for the help!

RideAnS [48]

Answer:

Using reflexive property (for side), and the transversals of the parallel lines, we can prove the two triangles are congruent.

Step-by-step explanation:

Since AB and DC are parallel and AC is intersecting in the middle, you can make out two pairs of alternate interior angles<em>.</em> These angle pairs are congruent because of the alternate interior angles theorem. The two pairs of congruent angles are: ∠DAC ≅ ∠BCA, and ∠BAC ≅ ∠DCA.
With the reflexive property, we know side AC ≅ AC.
Using Angle-Side-Angle theorem, we can prove ΔABC ≅ ΔCDA.

8 0

3 years ago

What is the nth term of the geometric sequence -2,10,-50

poizon [28]

Answer:

$T_n=-1(-5)^n^-^1$

Step-by-step explanation:

We are given;

A geometric sequence;

-2,10,-50

Required to determine the nth term

The nth term in a geometric sequence is given by the formula;

$T_n=a_1r^n^-^1$

where $a_1$ is the first term and r is the common ratio;

In this case;

$a_1=-2$

r = 10 ÷ -2

= -5

Therefore;

To get the nth term in the given geometric sequence we use;

$T_n=-1(-5)^n^-^1$

Thus, the nth term is $T_n=-1(-5)^n^-^1$

3 0

3 years ago

Solve the equation<br> -18 + 24 = -2(x+6)

anzhelika [568]

Answer:

x = -9

Step-by-step explanation:

-18+24 = -2(x+6) Distribute and simplify

6 = -2x-12 Add 12 to both sides

18 = -2x Divide by -2 on both sides

-9 = x Here's your answer

Hope this helps! :D

3 0

2 years ago

Read 2 more answers

(ASAP PICTURE ADDED) What is the simplified form of the following expression?

bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

$7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)$

WE need to simplify this equation.

Solve the parenthesis of each term.

$=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right$

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation: $=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)$

Adding like terms we get:

$=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\$

$(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)$

So, option c is correct

5 0

3 years ago

Read 2 more answers

At what value of x does the graph of the following function f(x) have a vertical asymptope? f(x)=5x/2x-6

Olegator [25]

I think it’s C hope it helps

7 0

4 years ago