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jenyasd209 [6]
3 years ago
8

In the first law of thermodynamics, triangle E=Q-W, what does Q stand for

Physics
1 answer:
Flura [38]3 years ago
4 0

As per first law of thermodynamics we know that

E = Q - W

here we know that

E = internal energy of the gas

Q = heat given to the system

W = work done by the system

So this is basically energy conservation law in which Q stands for the Heat energy given to the system

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The momentum of an ostrich is calculated to be 5,400 kg*km / hr Its mass is known to be 120 kg. Was the ostrich moving or standi
Dmitry [639]

The correct answer to the question is : The ostrich is motion.

EXPLANATION:

As per the question, the momentum of ostrich P = 5400 Kg. Km/hr.

The mass of the ostrich m = 120 Kg.

The momentum of a body is defined as the product of mass with velocity.

Mathematically P = mv.

The velocity of the ostrich v is calculated as -

                                           v = \frac{P}{m}

                                              = \frac{5400}{120}\ Km/hr

                                              = 45 Km/hr

Hence, the ostrich is in motion as it is moving with a velocity of 45 Km/hr.

7 0
3 years ago
Read 2 more answers
7. What is the weight of an infant whose mass is 1.76 kg?
stiks02 [169]

Answer:

3 pounds and 14.082 ounces (?)

Explanation:

F= M x 9.8

1.76 x 9.8 = 17.25 N

6 0
3 years ago
In what ways does a river carry its load?
MArishka [77]
It carry its loads from the sand and outher partials in it
7 0
3 years ago
Light of wavelength 650 nm is normally incident on the rear of a grating. The first bright fringe (other than the central one) i
garik1379 [7]

Answer

given,

wavelength (λ) = 650 nm

angle = 5°

using bragg's law

sin \theta = \dfrac{n \lambda}{d}

d= \dfrac{n \lambda}{sin \theta}

d= \dfrac{1 \times 650 \times 10^{-9}\ m}{sin5^0}

d = 7.46 x 10⁻⁴ cm

number of slits per centimeter

  = \dfrac{1}{d}\\\Rightarrow \dfrac{1}{7.46\times 10^{-4}}\\\Rightarrow 1340 split per centimeter.

b) wavelength of two rays  650 nm and 420 nm

 d = \dfrac{1}{5000}

     d =  2 x 10⁻6 m

    we now,

sin \theta = \dfrac{n \lambda}{d}

for 650 nm

sin \theta = \dfrac{2\times 650\times 10^{-9}}{2\times 10^{-6}}

\theta =sin^{-1}(0.65)

θ = 40.54°

for 450 nm

sin \theta = \dfrac{2\times 450\times 10^{-9}}{2\times 10^{-6}}

\theta =sin^{-1}(0.45)

θ = 24.83°

now, difference

|θ_{650} -θ_{420}| =40.54°-24.83°

|θ_{650} -θ_{420}| =19.71°

8 0
4 years ago
A 500 kilogram roller coaster starts from rest at the top of an 80 meter hill.What was its speed at the bottom at the hill?
GarryVolchara [31]

m = mass of the roller coaster = 500 kg

h = height of the hill = 80 m

v = speed of the roller coaster at the bottom of the hill = ?

using conservation of energy

kinetic energy at the bottom of the hill = potential energy at the top of hill

(0.5) m v² = m g h

(0.5) v² = g h

inserting the values

(0.5) v² = (9.8) (80)

v = 39.6 m/s

hence the speed at the bottom comes out to be 39.6 m/s

3 0
3 years ago
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