Answer:
48m
Explanation:
- Initial velocity = 4m/s
- Acceleration = 4m/s²
- Time = 4s
- Displacement = ?
From Second equation of motion ,
s = ut + 1/2at²
s = 4*4 + 1/2*4*(4)² m
s = (16 + 2 * 16) m
s = ( 16 + 32 )m
s = 48 m
Answer
given,
Initial speed of the car = 0 m/s
acceleration of car = 2.4 m/s²
Speed of the truck = 15.5 m/s
to car to overtake the truck distance travel by both should be same
distance traveled by the truck
d = 15.5 t
distance traveled by the car
d = u t + 1/2 gt ²
d = 0.5 x 9.8 t²
now, equating both the equations
15.5 t = 4.9 t²
t = 3.163 s
Time taken by car to overtake truck is 3.163 s
distance travel by the car = 15.5 x 3.163
d = 49 m
b) Speed of the automobile
using equation of motion
v = u + at
v = 0 + 2.4 x 3.163
v = 7.59 m/s
Speed of the automobile while crossing truck is equal to v = 7.59 m/s
1 Is correct because James is going faster.
2 is correct because a faster speed on a position vs time graph will have a steeper slope
3 is correct as well.
The answer is 4 all of the above
Answer:
1) Average velocities:
Given the magnitudes of 2 velocity vectors, in different time instants, the average velocity is defined as the difference of the 2 velocity magnitudes, in absolute value, divided by the interval of time occuring between the measurement of the velocity magnitudes.
2) Average acceleration
Given the magnitudes of 2 acceleration vectors, in different time instants, the average acceleration is defined as the difference of the 2 acceleration magnitudes, in absolute value, divided by the interval of time occuring between the measurement of the acceleration magnitudes.
As you see the definitions are pretty similar.
Note: I didn't copy-paste this answers from any other site.
