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3 years ago

In what ways does a river carry its load?

Physics

1 answer:

MArishka [77]3 years ago

7 0

It carry its loads from the sand and outher partials in it

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A hand pushes two blocks, A and B, along a frictionless table for a distance d. When the hand starts to push, the blocks are mov

Kitty [74]

net work = change in kinetic energy

for Block B, we just have the force from block A acting on it
F(ab)d= .5(1)vf² - .5(1)(2²)
F(ab)d= .5vf² - 2

Block A, we have the force from the hand going in one direction and the force of block B on A going the opposite direction

10-F(ba)d = .5(4)vf² - .5(4)(2²)
10-F(ba)d = 2vf² - 8
F(ba)d = 18 - 2vf²

now we have two equations:
F(ba)d = 18 - 2vf²
F(ab)d= .5vf² - 2

since the magnitude of F(ba) and F(ab) is the same, substitute and find vf (I already took into account the direction when solving for F(ab)

10-.5vf² + 2 = 2vf² - 8
12 - .5vf² = 2vf² - 8
20 = 2.5vf²
vf² = 8

they both will have the same velocity
KE of block A= .5(4)(2.828²) = 16 J
KE of block B=.5(1)(2.828²) = 4 J

5 0

4 years ago

What is the work function of cadmium metal if light with = 9.85×1014hz is necessary to eject electrons?

Alika [10]

We use the Planck’s formula:

E = hv

where,

E = energy, h = planck’s constant = 6.6x10^-34 J s, v = frequency in Hz (Hz = 1 / s)

Subsituting the values to find for E:

E = (6.6×10^-34 J s) * 9.85×10^14 / s

E = 6.5x10^-19 J

3 0

3 years ago

A kayaker paddles at 4.0 m/s in a direction 30° south of west. He then turns and paddles at 3.7 m/s in a direction 20° west of s

vichka [17]

Answer:

Magnitude of resultant velocity of kayaker to the nearest tenth = 10 m/s

Direction of resultant velocity of kayaker = 49.32⁰ South of west.

Explanation:

Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.

First kayaker paddles at 4.0 m/s in a direction 30° south of west, kayaker paddles at 4.0 m/s in a direction 210° anticlockwise from positive horizontal axis.

So velocity of kayaker = 4 cos 210 i + 4 sin 210 j = -3.46 i - 2 j

He then turns and paddles at 3.7 m/s in a direction 20° west of south, kayaker paddles at 3.7 m/s in a direction 250° anticlockwise from positive horizontal axis.

So that velocity = -1.27 i - 3.48 j

So resultant velocity of kayaker = -3.46 i - 2 j +(-1.27 i - 3.48 j) = -4.71 i - 5.48 j

Magnitude of resultant velocity of kayaker = $\sqrt{(-4.71)^2+(-5.48)^2} = 7.23 m/s$

Magnitude of resultant velocity of kayaker to the nearest tenth = 10 m/s

Direction of resultant positive horizontal axis, θ = tan⁻¹(-5.48/-4.71) = 229.32⁰ = 49.32⁰ South of west.

6 0

3 years ago

Read 2 more answers

State three factors that determine the strength of electromagnetic

Sunny_sXe [5.5K]

Answer:

Factors that affect the strength of electromagnets are the nature of the core material, strength of the current passing through the core, the number of turns of wire on the core and the shape and size of the core.Nov 28, 2020

Explanation:

7 0

3 years ago

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A 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.8 m/s left. Afterwards, the 282 kg car m

Leto [7]

Answer: momentum afterwards = 1040.4kgm/s

Explanation:

8 0

3 years ago