All categories

2 years ago

Which set of ordered pairs demonstrates a function?

Mathematics

1 answer:

Grace [21]2 years ago

4 0

Answer:

(3,4) (4,3) (9,7)

Step-by-step explanation:

this represents a function because none of the x's in the x values repeat

You might be interested in

What does unit rate mean

satela [25.4K]

Answer:

Unit rate describes how many units of the first type of quantity corresponds to one unit of the second type of quantity. Some common unit rates are miles, per hour, cost per item, earnings and per week

Step-by-step explanation:

6 0

3 years ago

Together a refrigerator and a desk cost $216. Find the price of each if the refrigerator costs three times as much as the desk

zheka24 [161]

Refrigerator 162$ and desk cost 54

6 0

3 years ago

Read 2 more answers

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

neonofarm [45]

Answer:

270 cm^2

Step-by-step explanation:

This is quite easy.

There is formula for it, the formula is bh/2

b= is the base or side that the triangle's altitude or height is perpendicular to.

h= is the height of the triangle or the altitude of the triangle.

I can always like to thing that a triangle is like half of a rectangle because the area for a rectangle is bh, but in a triangle it is half the bh.

b= 30

h=18

Now substitute the values in the formula

30(18)/2

30 times 18 = 540

divide the product by 2

540/2 = 270

6 0

2 years ago

Read 2 more answers

Did I do these two correctly?

natka813 [3]

Yes you did the equation on this page correctly.

7 0

3 years ago

x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco

igomit [66]

Answer:

$x=-cos(t)+2sin(t)$

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

$a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0$

Will have a characteristic equation of the form:

$a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0$

Where solutions $r_1,r_2...,r_n$ are the roots from which the general solution can be found.

For real roots the solution is given by:

$y(t)=c_1e^{r_1t} +c_2e^{r_2t}$

For real repeated roots the solution is given by:

$y(t)=c_1e^{rt} +c_2te^{rt}$

For complex roots the solution is given by:

$y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)$

Where:

$r_1_,_2=\lambda \pm \mu i$

Let's find the solution for $x''+x=0$ using the previous information:

The characteristic equation is:

$r^{2} +1=0$

So, the roots are given by:

$r_1_,_2=0\pm \sqrt{-1} =\pm i$

Therefore, the solution is:

$x(t)=c_1cos(t)+c_2sin(t)$

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of $x(t)$ in order to find the constants $c_1$ and $c_2$ :

$x'(t)=-c_1sin(t)+c_2cos(t)$

Evaluating the initial conditions:

$x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1$

And

$x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2$

Now we have found the value of the constants, the solution of the second-order IVP is:

$x=-cos(t)+2sin(t)$

3 0

3 years ago