3 years ago

Which set of ordered pairs demonstrates a function?

1 answer:

Grace [21]3 years ago

4 0

Answer:

(3,4) (4,3) (9,7)

Step-by-step explanation:

this represents a function because none of the x's in the x values repeat

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timofeeve [1]

try c im sorry if im wrong i tried

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3 years ago

andreyandreev [35.5K]

Answer:

3/1

Step-by-step explanation:

All unit rates have a denominator of 1.

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3 years ago

inn [45]

Lst question: x = 5, y = 7

2nd question: x = -1, y = 5

3rd question: x = 98, y = 80

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3 years ago

Fiesta28 [93]

11/21 would be the answer

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3 years ago

vazorg [7]

If $x+a$ is a factor of the polynomial, it means that $-a$ is a root of the polynomial.

In fact, if a polynomial $p(x)$ has a root $x_0$ (i.e. $p(x_0)=0$ ), then the polynomial is divisible by $(x-x_0)$

In your case, you know that the polynomial is divisible by $(x+a)=(x-(-a))$ , so $-a$ is a solution.

Let's evaluate $p(-a)$ and set it to zero:

$2(-a)^2+2a(-a)+5(-a)+10 = 0 \iff 2a^2-2a^2-5a+10=0 \iff -5a+10 = 0 \iff a = 2$

We can check the answer: if $a=2$ the polynomial becomes

$2x^2+2(2)x+5x+10 = 2x^2+9x+10$

And we're claiming that $-a=-2$ is a root of this polynomial:

$2(-2)^2+9(-2)+10 = 2\cdot 4 - 18 + 10 = 0$

5 0

3 years ago