Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
4 and 1/6 is the mixed number, or 4 and 2/12
Answer:
It's the first one
Step-by-step explanation:
Because 2M means you are multiplying all the values of M with 2
Question
the coordinates of point t are (0,2). the midpoint of st is (1,-6) find the coordinates of point s.
Answer:
(10,-14)
Step-by-step explanation:
0 + x
--------- = 5 Multiply both sides by 2 ----> 0 + x = 10 or x = 10
2
2 + y
-------- = -8 Multiply both sides by 2 ----> 2 + y = -16 or y = -14
2
Therefore, the coordinates of point S should be at (10,-14)
Answer: 8
Explanation: first start with the fractions. 4 divided by a (which equals 4) is 1. B (which equals 3) divided by 3 is 1. Then put it all together 6+1+1=8.
