Answer:
Step-by-step explanation:
Both functions are linear, as the highest power of x is 1 in each case.
The function represented by the table has a slope of 6, since each unit increase in x results in a unit increase of 6 in y.
The function g(x) = 2x + 6 has a slope of 2.
The y intercept of f(x) is (0, -6), which we can read directly from the table.
The y int. of g(x) is 6, which can be read directly from y = 2x + 6.
g(x) has the greater y-intercept: +6 versus -6.
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A square is a quadrilateral that has the same length on every side.
The area of the garden is 196 square feet. To find the area of a garden, you have to multiply the length times the width. Since you know that both widths are the same, you can simply just calculate the square root of 196. The square root of 196 is 14. So you know that one side is 14 feet in length.
Now you will need to find the perimeter. The perimeter of any polygon is the lengths of all sides added up. Since there are 4 sides on a square, and each side is the same length, you can just add 14, 4 times. 14+14+14+14 equals 56. So the perimeter of the garden is 56 feet.
Hannah will need 56 feet of fencing.
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Answer:
B. angle 5
Step-by-step explanation:
Answer:
f(x)=-3x+14
Step-by-step explanation:
we have
y+1=-3(x-5)
Isolate the variable y
Distributed right side
y+1=-3x+15
Subtract 1 both sides
y=-3x+15-1
Combine like terms
y=-3x+14
Convert to function notation
Let
f(x)=y
f(x)=-3x+14
Well, the answer quite simple ....there are 4! ways to arrange these numbers...and as 4! = 4*3*2*1 = 24
hence 24 is the correct answer....
u can also remember it by theorem of multiplication as.....in first place (I.e. first code can be any no. out of 4,5,2&7 ....so 4*.....
as first place is acquired by a certain no. that leaves three no. to fill third place and when third place I'd occupied it leaves 2 numbers to fill second place and lastly only one no. to fill the last place .....so it's result will be like 4*3*2*1.
I know this is pretty much confusing ....but still I tried my best....
if anything troubles u here feel free to ask me